Hydraulic Piston Pump

Question...

A log splitter uses a pump with hydraulic oil to push a piston, attached to which is a chisel. The pump can?

generate a pressure of 2.4x107 Pa in the hydraulic oil, and the piston has a radius of 0.064 m. In a stroke lasting 14 s, the piston moves 0.62 m. What is the power needed to operate the log splitter's pump?

Answers...

Answer by billrussell42
Area of the piston is πr² or π(0.064)² = 0.0001656 m²

force is 0.0001656 m² x 2.4e7 N/m² = 3974 N

work is force x distance = 3974 N x 0.62 m = 2464 J

power is work/time = 2464 J J / 14s = 176 watts

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